Calculating Percentage Abundance

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Calculating Percentage Abundance

Question

Element V exist as two isotopes FORM 3 Chemistry

FORM 3 Chemistry

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The relative atomic mass of a normal sample of V is 74.1. Deduce the relative percentage abundance of each Isotope.

Answer

FORM 3 Chemistry

Related Questions

Q. Element V has two isotopes. Two thirds of V and one third of V. What is the relative atomic mass of element V? Q. The following refers to element Y. Given that isotope C contains 31 neutrons in its nucleus find the number of protons in isotope B. Q. The table below shows the relative atomic masses and the percentage abundance of the isotopes L1 and L2 of element L. Calculate the relative atomic mass of element K. Q. An element M has two isotopes ⁶³M and ⁶⁵M . The relative atomic mass of the naturally occurring is 63.55. Calculate the percentage of each isotope. Q. The electronic structures for elements represented by letters A, B, C and D are: A 2.8.6; B 2.8.2; C2.8.1; D 2.8.8; Select the element which forms: A double charged cation. A soluble carbonate. Which element has the shortest atomic radius? Q. Two elements X and Y have their atomic number being 11 and 19 respectively. a. Show their electronic configurations. Are the elements in the same period or group, give a reason for your answer? Q. An element K has relative atomic mass of 36.2. Given that the element has two isotopes, A of atomic mass 35.0 and B of atomic mass 38.0. Calculate the relative percentage abundances of each of the isotopes. Q. Explain why atomic radii of element in any period decreases gradually from left to right in the periodic table. Q. 1.512g of metal carbonate XCO₃ react with 20 cm³ of 1.8M hydrochloric acid completely. calculate the relative atomic mass of element X (C = 12, O = 16).

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