Reaction of Hydrochloric Acid with Calcium Hydrogen Carbonate

Question

12.0 cm³ of 0.05 M hydrochloric acid reacted with calcium hydrogen carbonate to form calcium chloride, water and carbon IV oxide.
a. Write the chemical equation for the reaction
b. Calculate the number of moles of hydrochloric acid used
c. Determine the mass of calcium hydrogen carbonate used. (Ca = 40, C =12, H = 1,O=16)

Answer

a. Ca(HCO₃)₂ + 2HCl → CaCl₂ + CO₂ + H₂O

b. Moles of HCl = 0.05 x 12.0 = 0.006 -- is the formula right?

c. Mass of Ca(HCO₃)₂ = (40 + 2 + 24 + 6 + 16) x 0.003 (Answer not complete)

Related Questions

Q. 20.0cm³ of a solution containing 4g per litre of sodium hydroxide was neutralized by 8.0cm³ of dilute sulphuric (VI) acid. Calculate the concentration of sulphuric (VI) acid in moles per litre Na=23, 0=16 H=1 s=32. Q. Describe a chemical test to distinguish between hydrocarbons with the following molecular formula C₄H₁₀ and C₄H₈ respectively. Q. A compound has an empirical formula C₃H₆O and a relative formula mass of 116.a. Determine its molecular formula (H = 1.0, C = 12.0, O = 16.0). b. Calculate the percentage composition of carbon by mass in the compound.

Reaction of Hydrochloric Acid with Calcium Hydrogen Carbonate

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